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If search engines determine that your website is popular, then they will list it as relevant to a search, the more popular - the more relevant. The more relevant, the higher you will be listed in search results. But how easy is to be popular?
Design to become popular:
Key words:
For your subject, find websites in other parts of the world using your key words, but who don't directly compete with you. For your location, there are small business groups, local chambers of commerce, portals and other websites in your location looking for links for the same reason as you.
Non-reciprocal links:
Reciprocal links:
Websites in your own location are of value for the location words. e.g. If you want to be found in a search for Sydney websites, links from other Sydney sites can help. If you are selling toys in Sydney, a link from Joe's Pizzas New York is unlikely to help. Asking for a link:
Check where your link will be on the other site. Check that their home page links directly to their links page. Avoid websites where their link to you won't be direct. Run your mouse over their links to other sites. If a link looks like an internal database reference, e.g. resources.asp?ID=1234, it is too indirect to be counted by search engines. The link should be http://www.yourwebsite.com.
Many websites may ask you for reciprocal links. Evaluate these against the above criteria.
Placing a link:
Many websites will email you the HTML code for a link to them. You can copy and paste it on to your page, or your web designer can.
Supplying link details:
Be popular:
Some simple suggestionsWell I don't consider myself an expert, I do have experience with working with larger datasets and there are a couple of things that I always do to keep queries performing well. Optimize Queries with EXPLAIN
Optimizing joinsSingle sweep what?
Why is this important? Imagine a main table - tableA - with 80,000 rows of data. This table has a corresponding n:n table that maps entries in tableA with a locations table. A query could be written as: SELECT tableA.*, locations.location from tableA Left Join tableA2locations on tableA2locations.tableA_id = tableA.id Left Join locations on tableA2locations.location_id = locations.id where locations.location = 'sometown' Keeping the above quote in mind, MySQL will read a row from the first table and join the corresponding data from the joined tables for that row and then sweep thru the rest of the data, joining as it goes along. This leads us into the following section. Number of rows needed to execute a query
From the above, you can determine that for a query on tables that have not been properly indexed, a join can quickly become unwieldy when dealing simply with three tables with records in the thousands (1000*1000*1000 = a slow query). See HackMySQL for a good example of this. Reducing the number of rows needed to execute a querySo beyond indexing properly for joins, you can still end up with a query that runs in a way that causes a bottleneck. Taking our example from above, imagine that we use a where clause that limits the tableA selection to half ( SELECT tableA.*, locations.location from tableA Left Join tableA2locations on tableA2locations.tableA_id = tableA.id Left Join locations on tableA2locations.location_id = locations.id where locations.location = 'sometown' and tableA.foo = 'bar' This starts us out with 40,000 rows of tableA data to examine. If there are a further 2000 rows from tableA2locations, thats 800,000 rows of data. Not astronomical, but significant. If this was a 3 or 4 table join, things could get ugly. What to do? The answer may be obvious to some: select first with the most limiting table: SELECT tableA.*, locations.location from locations Left Join tableA2locations on tableA2locations.location_id = locations.id Left Join tableA on tableA2locations.tableA_id = tableA.id where locations.location = 'sometown' and tableA.foo = 'bar' This starts us out with 1 selection from the locations table, then 2000 from tableA2locations. If the join between tableA2locations and tableA is indexed correctly, we are then left with an index join based on ID, rather then having to initially select 40,000 rows from tableA as in the previous example. When I first started programming, it made sense to me to select from the main table (tableA) and join the lookups. But once you add some data to the mix and start to play with For further reading on the topic, I always send people to HackMySQL when they ask, so for more tips and tricks, be sure to have a read thru the optimize section of that site. Article Index: | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | 26 | 27 | 28 | 29 | 30 | 31 | 32 | 33 | 34 | 35 | 36 | 37 | 38 | 39 | 40 | 41 | 42 | 43 | 44 | 45 | 46 | 47 | 48 | 49 | 50 | 51 | 52 | 53 | 54 | 55 | 56 | 57 | 58 | 59 | 60 | 61 | 62 | 63 | 64 | 65 | 66 | 67 | 68 | 69 | 70 | 71 | 72 | 73 | 74 | 75 | 76 | 77 | 78 | 79 |
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